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Newton's Law of Cooling Calculator — Find Temperature at Time t or Time to Cool

Calculate an object's temperature after any time using Newton's Law of Cooling: T(t) = T_env + (T_0 − T_env) × e^(−k·t). Find cooling time to a target temperature, half-cooling time, and 99% equilibrium time. Supports °C, °F, K; seconds, minutes, hours.

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Calculation Parameters

°C
°C
1/min
Examples: hot tea/coffee ≈ 0.017 | metal in air ≈ 0.03–0.08 | well insulated ≈ 0.005
°C

Enter Parameters

Fill in the form on the left and click "Calculate"

Newton's Law of Cooling Calculator

This calculator applies Newton's Law of Cooling to predict how an object's temperature changes over time as it exchanges heat with its surroundings. Whether you want to know how quickly a hot cup of coffee cools down, how long a metal ingot takes to reach room temperature, or how fast a human body cools in a cold environment — this tool gives you the answer instantly.

Thermal Conduction and Convection

There are three main mechanisms of heat exchange: thermal conduction, convection, and radiation. Newton's Law of Cooling applies best when conduction and convection dominate — for example, the cooling of a cup of tea or a hot metal object in still air. In these cases, the primary heat exchange happens at the surface between the object and the surrounding medium. Warm liquid evaporates and convection carries heat away from the surface, gradually lowering the object's temperature.

How fast things cool depends on two factors:

  • The temperature difference between the object and its surroundings — the larger the difference, the faster the cooling.
  • The cooling coefficient k — which depends on the material, shape, surface area, and heat transfer mechanism.

Newton's Law of Cooling Formula

The formula is:

T(t) = Tenv + (T0 − Tenv) × e−k·t

Where:

  • T(t) — temperature of the object at time t
  • Tenv — ambient (environment) temperature
  • T0 — initial temperature of the object
  • k — cooling coefficient [min−1] (rate of heat loss)
  • t — elapsed time
  • e — Euler's number ≈ 2.71828

The cooling coefficient k can be expressed as:

k = hA / C

Where:

Typical Cooling Coefficients

Object Cooling coefficient k (per minute) Condition
Cup of hot coffee/tea (ceramic, 250 ml) ≈ 0.017 Room temperature ~20°C, no lid
Cup of hot coffee (with lid) ≈ 0.010 Room temperature ~20°C, insulated lid
Small metal object in still air ≈ 0.03–0.08 Forced convection increases k
Human body (in water at 15°C) ≈ 0.02–0.04 Rapid cooling — hypothermia risk
Large metal casting ≈ 0.001–0.005 Low surface-to-mass ratio

How Long Does a Cup of Tea Take to Cool?

Starting at 90°C with an ambient temperature of 20°C and a typical ceramic mug cooling coefficient of k = 0.017/min:

  • After 10 minutes: T ≈ 79°C
  • After 20 minutes: T ≈ 69°C
  • After 30 minutes: T ≈ 60°C (comfortably warm)
  • After 60 minutes: T ≈ 43°C (still warm)
  • After 120 minutes: T ≈ 29°C (nearly room temperature)

Key Derived Values

  • Half-cooling time — time for the object to lose half the temperature difference to the environment:
    t½ = ln(2) / k ≈ 0.693 / k
  • 99% equilibrium time — time to reach 99% of ambient temperature:
    t99 = ln(100) / k ≈ 4.605 / k

Units Supported

This calculator supports:

  • Temperature: Celsius (°C) — metric system; Fahrenheit (°F) — US/imperial; Kelvin (K) — SI base unit
  • Time: seconds, minutes, hours

Note: Newton's Law uses temperature differences, which are numerically identical in °C and K. In °F, a 1°F difference equals 5/9°C. The cooling coefficient k must always match the time unit used in the calculation.

FAQs

Is Newton's Law of Cooling accurate?

It is an excellent approximation when the temperature difference between the object and environment is not too large (less than ~50°C), and when forced convection is small. For large temperature differences or highly dynamic conditions, more complex heat transfer equations are needed.

How do I find the cooling coefficient k experimentally?

Measure the temperature of your object at two time points t1 and t2, then use:
k = −ln[(T2 − Tenv) / (T1 − Tenv)] / (t2 − t1)

Does the formula work for heating too?

Yes! If the object is colder than the environment, the same formula describes heating. The temperature difference becomes negative, and the object warms exponentially toward Tenv.

Calculation History

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